How do you graph the inequality x> 5 or x <− 2? Algebra Linear Inequalities and Absolute Value Multi-Step Inequalities

Circle A: (x - color (red) (5))^2 + (y - color (red) (2))^2 = color (blue) (sqrt (15))^2 (x - color (red) (5))^2 + (y - color (red) (2))^2 = 15 graph { ( (x-5)^2+ (y-2)^2-15)=0 [-50.

Mar 22, 2018 · (x-5)^2+(y+2)^2=(sqrt12)^2 is a circle with center (5,-2) and radius sqrt12 This is a quadratic equation in two variables, where one - coefficients of x^2 and y^2 are equal and two - the …

The graph is inserted. graph {y>=2x^2-2x-5 [-6, 6, -12, 12]} y = 2x^2-2x-5=2 (x-1/2)^2-11/2, giving the standard form (x-1/2)^2=4 (1/8) (y+11/2) The vertex ( least-y point ) of this parabola is (1/2, -11/2). …

How do you graph the circle with center at (-4, 2) and radius 5 and label the center and at least four points on the circle, then write the equation of the circle?

How do you write an equation for a rational function that has a vertical asymptote at x=2 and x=3, a horizontal asymptote at y=0, and a y-intercept at (0,1)?

The graph of this function is given below :- graph {3sin (2x)+5 [-25.66, 25.67, -12.83, 12.83]} OR You can use another test to check if it is not one-one function :- Draw a horizontal line parallel to X-axis …

Jul 14, 2016 · The advantage of having the equation in this form is that m and b , may be extracted 'easily'. Express x - y = 5 in this form. Multiply terms on both sides by -1 Hence -x +y = -5 → y = x - 5 …

May 22, 2018 · The region in quadrant 1 under the graph of #y=4-x^2# is rotated about the line to form a solid. Find the volume of the solid. Calculus

f(x) = -1/2(x-3)(x+3) for x in [-3,+3] f(x)=1/2(x-3) for x in (3,5] From the picture we can see that f(x) is a piecewise function. I will assume that the domain of f(x) is entirely shown in the picture. :. Domain of …